integrate (4x ^ 3 - 12x ^ 2 - x + 2) dx.... Question from @aleyseean

Jawab:

∫ (4x³ - 12x² - x + 2) dx =

$\frac{4}{3+1}$ x⁽³⁺¹⁾ - $\frac{12}{2+1}$ x⁽²⁺¹⁾ - $\frac{1}{1+1}$ x⁽¹⁺¹⁾ + 2x⁽⁰⁺¹⁾ + c =

x⁴ - 4x³ - 1/2 x² + 2x + c

6 votes Thanks 5

aleyseean ka, boleh bantu soalku satu lagi ga ka []

SelamatMenikmati eh maaff baru liat :") masih perlu ga ya??

aleyseean ada satu soal ka, hehe

aleyseean makasih banyak kak!

SelamatMenikmati coba kakk hehe siapa tau bisa bantu

aleyseean iyaa

misrokhah439

$\small\boxed{\bf{\int_{ }^{ }( {4x}^{3} - {12x}^{2} - x + 2) dx=\boxed{\bf{ {x}^{4} - {4x}^{3} - \frac{ {x}^{2} }{2} + 2x + C}}}}$

Penyelesaian:

$\displaystyle \rm\int( {4x}^{3} - {12x}^{2} - x + 2) \: dx$

${\tt={\displaystyle \rm\int4x^{3} \: dx - \displaystyle \rm\int {12x}^{2} \: dx - \displaystyle \rm\int \: x \: dx + \displaystyle \rm\int2 \: dx}}$

$= \rm{x}^{4} - {4x}^{3} - \frac{ {x}^{2} }{2} + 2x$

$= \rm{x}^{4} - {4x}^{3} - \frac{ {x}^{2} }{2} + 2x + C$

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Mohon Di Geser

1 votes Thanks 2

misrokhah439 jangan lupa untuk di geser ya^^

aleyseean oh iya, makasih kak!