Misal : u = 2-x
du = -1 dx
dx = -du/1
Integral x³ (2-x)^5 dx =
x³ (u)^5.(-du/1) =
-x³.1/6.u^6 + C =
-x³/6 (2-x)^6 + C =
(-x³ (2-x)^6 / 6) + C
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Misal : u = 2-x
du = -1 dx
dx = -du/1
Integral x³ (2-x)^5 dx =
x³ (u)^5.(-du/1) =
-x³.1/6.u^6 + C =
-x³/6 (2-x)^6 + C =
(-x³ (2-x)^6 / 6) + C