Question

Integral tentu dari
x(x-2)(x-1) dengan batas atas 2 dan batas bawah 1

Answer 1

Verified answer

InTegraL Tentu

∫x(x - 2)(x - 1) dx [2...1]
= ∫(x³ - 3x² + 2x) dx
= 1/4 x⁴ - x³ + x² [2...1]
= (1/4 . 2⁴ - 2³ + 2²) - (1/4 . 1 - 1 + 1)
= (4 - 8 + 4) - 1/4
= 0 - 1/4
= -1/4