Question

Integral dari x.akar(9 + x^2) dx
Batas 0 sampai 3

Answer 1

Int(0-3) x . √(9+x²) dx
mis: u = (9+x²)
du = 2x dx
dx = du/2x
x=0 >> u=9
x=3 >> u=18
int(9-18) x/2x . √u du
int(9-18) 1/2 . u^½ du
⅓ . u . √u batas(9-18)
⅓ . 18 . √18 - ⅓ . 9 . √9
6 . 3√2 - 9
18√2 - 9

Answer 2

Int(0-3) x . √(9+x²) dx mis: u = (9+x²) du = 2x dx dx = du/2x x=0 >> u=9 x=3 >> u=18 int(9-18) x/2x . √u du int(9-18) 1/2 . u^½ du ⅓ . u . √u batas(9-18) ⅓ . 18 . √18 - ⅓ . 9 . √9 6 . 3√2 - 9 18√2 - 9