u=sin2x
du=2cos2x dx ===½du=cos2x dx
int cos^3 (2x) sin ^5 2x dx =
int ( cos² (2x) sin ^5 2x) cos2x dx
int ( (1-sin² 2x) sin ^5 2x) cos2x dx
int ( (sin^5 2x -sin^7 2x) ) cos2x dx
int(u^5- u^7) ½ du
½(1/6 u^6- 1/8 u^8) + c
½(1/6 sin^6 2x - 1/8 sin^8 2x) + c
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u=sin2x
du=2cos2x dx ===½du=cos2x dx
int cos^3 (2x) sin ^5 2x dx =
int ( cos² (2x) sin ^5 2x) cos2x dx
int ( (1-sin² 2x) sin ^5 2x) cos2x dx
int ( (sin^5 2x -sin^7 2x) ) cos2x dx
int(u^5- u^7) ½ du
½(1/6 u^6- 1/8 u^8) + c
½(1/6 sin^6 2x - 1/8 sin^8 2x) + c