∫6x(x - 1) dx
= 6 × ∫x × (x - 1) dx
= 6 × ∫x² - x dx
= 6(∫x² dx - ∫x dx
= 6
= 2x³ - 2x²
= 2x³ - 2x² + C
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
∫6x(x - 1) dx
= 6 × ∫x × (x - 1) dx
= 6 × ∫x² - x dx
= 6(∫x² dx - ∫x dx
= 6
= 2x³ - 2x²
= 2x³ - 2x² + C