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Verified answer
Integral (2 cos²x -1) dxcos²x = (1+cos2x) /2
Integral (2 cos²x -1) dx
= Integral 2(1+cos2x) /2 -1 dx
= Integral ((1+cos2x) -1) dx
= integral cos2xdx
= 1/2 × sin2x -x +c
= 1/2 sin2x -x+c