Question

Ini juga tolong ya, pakai cara :D

Answer 1

ˣlog(x+6) = ˣlog 2⁴ - ˣlog x
ˣlog(x+6) = ˣlog(16/x)
x+6 = 16/x , dgn batas x +6 > 0 ∩ x > 1 --> x > 1
.
x + 6 = 16/x ...kalikan x
x² + 6x = 16
x² + 6x - 16 = 0
(x -2)(x+8) = 0
x = 2 atau x = - 8  (TM krn x < 1)
HP  x = 2

8)
³log(x²+1) . ⁵log 3 = ⁵log (x+21)
⁵log 3 . ³log(x²+1) = ⁵log (x+21)
⁵log (x²+1) = ⁵log (x+21)
x² +1 = x + 21 , dgn batas x+21 > 0 --> x > - 21

x² + 1 = x + 21
x² - x +1 - 21  = 0
x² -x  - 20 = 0
(x-5)(x+4)=0
x = 5 atau x = - 4