Ini gimana caranya ?.... Question from @luluzainal

October 2018 2 13 Report

Ini gimana caranya ?

MicoArrafi $$\begin{align} \frac{2}{2\sqrt3}&=\frac{1}{\sqrt3}\\&=\frac{\sqrt3}{\sqrt{3^2}}\\&=\boxed{\frac{1}{3}\sqrt3}\\\\\frac{2}{2+\sqrt3}&=\frac{2}{2+\sqrt3}\times\frac{2-\sqrt3}{2-\sqrt3}\\&=\frac{4-2\sqrt3}{2^2-\sqrt{3^2}}\\&=\frac{4-2\sqrt3}{4-3}\\&=\boxed{4-2\sqrt3}\ $atau$\ \boxed{2\ (\ 2-\sqrt3\ )} \end$

2 votes Thanks 1

luluzainal makasih yaa

acim A. 2/2V3
= 1/V3
= 1/V3 . V3/V3
= 1/3 V3

b. 2 / (2 + V3)
= 2 / (2 + V3) * (2 - V3)/(2 - V3)
= 2(2 - V3) / (2^2 - V3^2)
= (4 - 2V3) / (4 - 3)
= 4 - 2V3

2 votes Thanks 1

luluzainal makasih yaa

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