Question

Ini dia soal matematika pliss apalagi no 3 dan 4

Answer 1

1. int (2x² + 4x - 5) dx
= (2/3)x³ + 2x² - 5x + c

3. int [ -1 s/d 2] (2x - 1)⁴ dx
= 1/(2(4 + 1)) (2x - 1)⁵ [-1 s/d 2]
= (1/10)(2x - 1)⁵ [-1 s/d 2]
= ((1/10)(3)⁵) - ((1/10)(-3)⁵)
= (1/10)(3⁵ + 3⁵)
= (1/5)3⁵

Answer 2

2) int 5x . 3'√x² dx
= int 5x . x^(2/3) dx
= int 5x^(5/3) dx
= 5 * (3/8)x^(8/3) + C
= (15/8)x^8/3 + C

4) int [2,4] (x³-1)/(x-1) dx
= int [2,4] (x-1)(x²+x+1)/(x-1) dx
= int [2,4] (x²+x+1) dx
= [1/3 x³ + 1/2 x² + x] [2,4]
= (1/3 (4)³ + 1/2 (4)² + 4) - (1/3 (2)³ + 1/2 (2)² + 2)
= (64/3  + 12) - (8/3 + 4)
= 8 + 56/3
= 80/3