a. <ABC=90+45
13x+5=135
13x=135-5
13x=130
x=10
b. <CDF=3x
= 3 x 10
= 30°
c. 180°=<CFD+FDC+DCF
= 25+30+<DCF
<DCF=180-55
=125°
d. 180°= <DCF+<BCF
= 125+<6y+7
6y+7=180-125
6y=55-7
= 48
y = 8°
e. <BCF=6y+7
= 6 x 8 + 7
= 48+7
= 55°
f. <ABF=13x+5
=13 x 10 + 5
=135°
g. <CBF=180-135
= 45°
h. <BFC=180-(<CBF+<BCF)
8z=180-(45+55)
=180-100
8z=80
z=10°
i. <BFD=<BFC+CFD
=8z + 25
=80+25
=105°
j. x+y+z=10+8+10
=28°
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a. <ABC=90+45
13x+5=135
13x=135-5
13x=130
x=10
b. <CDF=3x
= 3 x 10
= 30°
c. 180°=<CFD+FDC+DCF
= 25+30+<DCF
<DCF=180-55
=125°
d. 180°= <DCF+<BCF
= 125+<6y+7
6y+7=180-125
6y=55-7
= 48
y = 8°
e. <BCF=6y+7
= 6 x 8 + 7
= 48+7
= 55°
f. <ABF=13x+5
=13 x 10 + 5
=135°
g. <CBF=180-135
= 45°
h. <BFC=180-(<CBF+<BCF)
8z=180-(45+55)
=180-100
8z=80
z=10°
i. <BFD=<BFC+CFD
=8z + 25
=80+25
=105°
j. x+y+z=10+8+10
=28°
Jawab:pake cara kelilinh
Penjelasan dengan langkah-langkah: