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2'log 3 . 3'log 7 = 2'log 7 = ab
7'log 2 = 1/(ab)
.
14'log 56= 2'log 56/ 2'log 14 = (2'log 2^3 + 2'log 7)/(2'log 2+2'log 7)
=[ 3. 2'log 2 + 2'log 7 ] / [ 2'log2 + 2'log 7]
= [ 3 + ab ] / [ 1 + ab ]
.
42'log 28 = 2'log 28 / 2'log 42 = (2'log 2^2. 7)/ (2'log 6.7)
= [ 2'log 2^2 + 2'log 7 ] / [ 2'log 2 + 2'log 3 + 2'log 7]
= =[ 2 + ab ] / [ 1 + a+ ab]