Respuesta:
[tex] \red{ \large \boxed{ \boxed{x < \frac{15}{31} } } } [/tex]
Explicación paso a paso:
[tex] \frac{4x + 1}{13} > \frac{3x - 1}{2} \\ \\ 2(4x + 1) >( 3x - 1)13 \\ \\ 8x + 2> 39x - 13 \\ \\ 8x - 39x > - 13 - 2 \\ \\ - 31x > - 15 \\ \\x > \frac{ -15}{ - 31} \\ \\ x < \frac{15}{31} [/tex]
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Verified answer
Respuesta:
[tex] \red{ \large \boxed{ \boxed{x < \frac{15}{31} } } } [/tex]
Explicación paso a paso:
[tex] \frac{4x + 1}{13} > \frac{3x - 1}{2} \\ \\ 2(4x + 1) >( 3x - 1)13 \\ \\ 8x + 2> 39x - 13 \\ \\ 8x - 39x > - 13 - 2 \\ \\ - 31x > - 15 \\ \\x > \frac{ -15}{ - 31} \\ \\ x < \frac{15}{31} [/tex]