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x² (x² - 1) < 16 (x² - 1); simplificamos x² - 1, siempre que |x| ≠ 1
x² < 16; o bien |x| < 4
- 4 < x < 4; suprimiendo x = - 1, x = 1 o bien:
1 < x < 4 ó - 4 < x < - 1
Saludos Herminio