Ile wynosi masa azotu zawartego w butli o pojemności 200dm3 pod ciśnieniem 1200hPa w temperaturze 30stC?
pv=nRt/Rt
t=30+273 303Kn=1200*200/83,1*303n=240000/25179,3n=ok.9,53 moli1mol=28g9,53mol=xx=ok.266,89g
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pv=nRt/Rt
t=30+273 303K
n=1200*200/83,1*303
n=240000/25179,3
n=ok.9,53 moli
1mol=28g
9,53mol=x
x=ok.266,89g