Ile wynosi ciezar bryłki zelaza. Obietosc 200cm szesciennych. Gestosc zelaza 7800kg na m szescienny
V = 200cm3 = 0,2dm3 = 0,0002m3d = 7800 kg/m3m = V * d
m = 0,0002m3 * 7800 kg/m3m = 1,56kg = 1560gF (ciężar) = m * g
g = stała 10N/kg
F = 1,56kg * 10kg/NF = 15,6 NOdp. Ciężar wynosi 15,6N.
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V = 200cm3 = 0,2dm3 = 0,0002m3
d = 7800 kg/m3
m = V * d
m = 0,0002m3 * 7800 kg/m3
m = 1,56kg = 1560g
F (ciężar) = m * g
g = stała 10N/kg
F = 1,56kg * 10kg/N
F = 15,6 N
Odp. Ciężar wynosi 15,6N.