ile trzeba dostarczyć ciepła bryle lodu o masie 1kg i temperaturze -10C ,aby zamienić ją w wodę o temperaturze 30C
Q= Q₁+Q₂+Q₃
Q₁= m*cw* Δt
Q₁= 1kg * 2100 J/kg* ⁰C * (-10⁰C- 0⁰C)
Q₁= 1kg * 2100 J/kg* ⁰C * 10⁰C
Q₁= 21000J
Q₂= m* ct
Q₂= 1kg * 334000J/⁰C
Q₂=334000J
Q₃= m*cw* Δt
Q₃= 1kg * 4200J/kg* ⁰C * (30⁰C- 0⁰C)
Q₃= 1kg * 4200J/kg* ⁰C *30⁰C
Q₃= 1260000J
Q= 21000J + 334000J + 1260000J
Q= 1615000J = 1615kJ
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Q= Q₁+Q₂+Q₃
Q₁= m*cw* Δt
Q₁= 1kg * 2100 J/kg* ⁰C * (-10⁰C- 0⁰C)
Q₁= 1kg * 2100 J/kg* ⁰C * 10⁰C
Q₁= 21000J
Q₂= m* ct
Q₂= 1kg * 334000J/⁰C
Q₂=334000J
Q₃= m*cw* Δt
Q₃= 1kg * 4200J/kg* ⁰C * (30⁰C- 0⁰C)
Q₃= 1kg * 4200J/kg* ⁰C *30⁰C
Q₃= 1260000J
Q= 21000J + 334000J + 1260000J
Q= 1615000J = 1615kJ