Question

Ile to gram : 0,6 mola CaCO3
ile to moli : 50gCuSO4
ile cząsteczek jest w 5dm^3 O2

Answer 1

1.

M CaCO3= 40g/mol + 12g/mol + 3*16g/mol =  100g/mol

 

1 mol ------- 100g

0,6 mola------ x

 

x= 0,6 mola*100g / 1 mol = 60g

 

2.

M CuSO4 = 64g/mol + 32g/mol + 4*16g/mol = 160g/mol

 

1 mol-------160g

   x    -------- 50g

 

x= 50g*1mol / 160g= 0,3125 mola

 

3.

22,4 dm3 ------ 6,02*10^23

5dm3 --------x

 

x= 5dm3  x  6,02*10^23 / 22,4 dm3 = 1,344*10^23

Answer 2

Ile to gram : 0,6 mola CaCO3

M CaCO3= 100g/mol

 

1mol- 100g

0,6mol- x

x= 60g

 

Ile to moli : 50g CuSO4

M CuSO4= 160g/mol

 

1mol- 160g

x- 50g

x= 0,3125mol

 

Ile cząsteczek jest w 5dm^3 O2

 

22,4dm^3- 6,02*10^23cz

5dm^3- x

x= 1,34375*10^23cz