Ile soli nalezy wsypac do roztworu 4 % o masie 250g aby powstal roztwor o stezeniu 20%?
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xg 100% ........................ 20-4=16
..................... 20%
250g 4% ..................... 100-20=80
x/250 = 16/80
80x = 16*250
80x = 4000
x = 50g soli