Ile powstanie siarczku rtęci (II) w reakcji 8g siarki z rtęcią
mS=32u
mHgS=233u
Hg + S---->HgS
32g S -----233g HgS
8g S ------xg HgS
x = 58,25g HgS
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mS=32u
mHgS=233u
Hg + S---->HgS
32g S -----233g HgS
8g S ------xg HgS
x = 58,25g HgS