ile potrzeba tlenu aby spalic 1 kg metanu całkowicie ?
Metan - CH4
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mCH₄=16u
mO₂=32u
CH₄ + 2 O₂ ---> CO₂ + 2H₂O
16g metanu ---- 2*32g tlenu
1kg metanu ---- x kg tlenu
x = 4kg tlenu