Ile moli tlenu O2 potrzeba do utlenienia 2gFe do:
a. FeO
b.Fe2O3
c.Fe3O4
mFe=56u
a)
2Fe+O₂-->2FeO
2*56g Fe ---------- 1mol O₂
2g Fe -------------- xmol O₂
x=2g*1mol/112g
x=0,018mol
b)
4Fe+3O₂-->2Fe₂O₃
4*56g Fe ---------- 3mol O₂
2g Fe -------------- x mol O₂
x=2g*3mol/224g
x=0,027mol
c)
3Fe+2O₂-->Fe₃O₄
3*56g Fe ----------- 2mol O₂
2g Fe --------------- xmol O₂
x=2g*2mol/168g
x=0,024mol
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mFe=56u
a)
2Fe+O₂-->2FeO
2*56g Fe ---------- 1mol O₂
2g Fe -------------- xmol O₂
x=2g*1mol/112g
x=0,018mol
b)
4Fe+3O₂-->2Fe₂O₃
4*56g Fe ---------- 3mol O₂
2g Fe -------------- x mol O₂
x=2g*3mol/224g
x=0,027mol
c)
3Fe+2O₂-->Fe₃O₄
3*56g Fe ----------- 2mol O₂
2g Fe --------------- xmol O₂
x=2g*2mol/168g
x=0,024mol