[tex]\dfrac{2^8+2^8+2^8+2^8}{8^2}=\dfrac{4\cdot2^8}{(2^3)^2}=\dfrac{2^2\cdot2^8}{2^6}=2^2\cdot 2^2=2^4[/tex]
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[tex]\dfrac{2^8+2^8+2^8+2^8}{8^2}=\dfrac{4\cdot2^8}{(2^3)^2}=\dfrac{2^2\cdot2^8}{2^6}=2^2\cdot 2^2=2^4[/tex]