pustynnaróża
Tlenek żelaza III => Fe203 M Fe203 = 2*56 + 3*16 = 160 g M Fe = 56 g 112 g Fe ----------------------- 160 g Fe2O3 x g Fe ---------------------------- 20g Fe203 x = 20 * 112 / 160 = 14 g Fe LUB : 112 / x = 160 / 20 160x = 112 *20 160 x = 2240 |:160 x= 14 g
M Fe203 = 2*56 + 3*16 = 160 g
M Fe = 56 g
112 g Fe ----------------------- 160 g Fe2O3
x g Fe ---------------------------- 20g Fe203
x = 20 * 112 / 160 = 14 g Fe
LUB :
112 / x = 160 / 20
160x = 112 *20
160 x = 2240 |:160
x= 14 g