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2 H20 ---->2 H2 + O2
16g x
4g-36g
xg-16g
x=1,7 g wodoru
myslę ze bedzie tak:) ale nie daje 100% pewności
2*mH₂O = 2*(2*1u+16u) = 2*18u = 36u
2*mH₂ = 2*2*1u = 4u
36u to 16g
4u to x
x= (16*4)/36 = 64/36 = 1,(7)g (jeden i siedem dziewiątych)