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mP₄ O₁₀=285u
4P + 5O₂ → P₄ O₁₀
4mole P ----- 284g P₄ O₁₀
0,5mola P --- xg P₄ O₁₀
x = 35,5g P₄ O₁₀
2)
mAl=27uAl₂O₃ + 3H₂ → 2Al + 3H₂O
54g Al ---- 3mole H₂O
xg Al ----- 0,6mola H₂O
x = 10,8g Al