Masa roztworu 200g
Cp1 = 20%
ms1 = 200*0,2 = 40g
x- ilość dodanej soli
Cp2 = 50%
Układamy równanie
= 100+0,5x = 40 + x ====> -0,5x = -60 x = 120g soli
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Masa roztworu 200g
Cp1 = 20%
ms1 = 200*0,2 = 40g
x- ilość dodanej soli
Cp2 = 50%
Układamy równanie
= 100+0,5x = 40 + x ====> -0,5x = -60 x = 120g soli