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mS=32u
mAl2S3=150u
2Al + 3S---->Al2S3
2*27g Al------3*32g S
xg Al----------10g S
x=5,6g Al
W nadmiarze użyto Al, więc
96g S-----150g Al2S3
10g S------xg Al2S3
x=15,6g Al2S3