Ile gramów NaO3 trzeba dodać do 150g 10% roztworu aby otrzymać roztwór 33%
150g 10%.............100-33=67
................33%
xg 100%................33-10=23
150/x = 67/23
67x = 150*23
67x = 3450
x = 51,49g NaOH
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150g 10%.............100-33=67
................33%
xg 100%................33-10=23
150/x = 67/23
67x = 150*23
67x = 3450
x = 51,49g NaOH