Ile gramów magnezu przereguje z 11 gramami dwutlenku węgla? ( produkty reakcji: tlenek magnezu i węgiel )
mMg=24g
mCO₂=12g+2*16g=44g
2Mg+CO₂-->2MgO+C
2*24g ----------------------- 44g
xg ---------------------------- 11g
xg=48g*11g/44g
xg=12g
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mMg=24g
mCO₂=12g+2*16g=44g
2Mg+CO₂-->2MgO+C
2*24g ----------------------- 44g
xg ---------------------------- 11g
xg=48g*11g/44g
xg=12g