Ile gramow FeS powstanie w reakji w ktorej siarka zwiaze 3,011 * 10 do potegi 23 atomow zelaza.
mFeS=88u
Fe + S ---> FeS
6,02*10^23 at. siarki ------ 88g FeS
3,011*10^23 at. siarki ----- xg FeS
x = 44g FeS
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mFeS=88u
Fe + S ---> FeS
6,02*10^23 at. siarki ------ 88g FeS
3,011*10^23 at. siarki ----- xg FeS
x = 44g FeS