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m molowa Fe₂O₃ = 2*56g + 3*16g = 160g
160g Fe₂O₃ - 112g Fe
20g Fe₂O₃ - x
160x = 112*20
160x = 2240 /:160
x = 14g
próbka 20 g tlenku żelaza (III) zawiera 14g żelaza