Question

Ile gram soli mgso4 przygotowano w celu sporzadzenia 300 cm3 2,5 molowego roztworu tej soli

Answer 1

v=0,3dm3

Cm=2,5mol/dm3

n=Cm*v

n=2,5*0,3

n = 0,75mola

 

M MgSO4=120g/mol

n=0,75mola

m=M*n

m=120*0,75

m = 90g MgSO4

Answer 2

m=?    Vr=300cm3=0,3dm3     Cm=2,5mol/dm3

 

MMgSO4=24+32+64=120g/mol

 

Cm=n/V

n=Cm*V

n=0,75mol

 

n=m/M

m=n*M

m=90g