ile gram NaOH potrzeba do zobojetnienia 12 g kwasu fosforowego (V)?
mNaOH=40u
mH3PO4=98u
3NaOH + H3PO4---->Na3PO4 + 3H2O
120g NaOH-------98g H3PO4
xg NaOH----------12g H3PO4
x = 14,7g NaOH
M(NaOH)=23g+16g+1g=40g
M(H3PO4)=3*1g+31g+4*16g=98g
3NaOH + H3PO3 -->Na3PO4+3H2O
3*40g---------98g
xg-------------12g
xg=120g*12g/98g
xg=14,7g
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mNaOH=40u
mH3PO4=98u
3NaOH + H3PO4---->Na3PO4 + 3H2O
120g NaOH-------98g H3PO4
xg NaOH----------12g H3PO4
x = 14,7g NaOH
M(NaOH)=23g+16g+1g=40g
M(H3PO4)=3*1g+31g+4*16g=98g
3NaOH + H3PO3 -->Na3PO4+3H2O
3*40g---------98g
xg-------------12g
xg=120g*12g/98g
xg=14,7g