Ile g jodku litu należy dodać do 56g 12% roztworu, aby otrzymać roztwór 17%
xg 100%.............................17 - 12 = 5
.....................17%
56g 12%............................100 - 17 = 83
x/56 = 5/83
83x = 5*56
83x = 280
x = 3,37g LiJ
Należy dosypać 3,37g LiJ
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xg 100%.............................17 - 12 = 5
.....................17%
56g 12%............................100 - 17 = 83
x/56 = 5/83
83x = 5*56
83x = 280
x = 3,37g LiJ
Należy dosypać 3,37g LiJ