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t=5 st C
V=0,5m *0,2m*03m=5dm *2dm*3dm=30dm3
1dm3=1kg a więc masa wody=30kg
cw wody=4200 J/kg *stC
szukane:
E=?
E=m *cw *t
E=30 kg *4200J/kg *st C *5 st C
E=630000J=630kJ
odp: musimy dostarczyć 630 kJ energii.