Ile energii należy dostarczyć do 100 gram lodu o temperaturze -10*C aby lód się stopił?
m=100g=0,1kg
Δt=10°C
c=2100J/kg·°C
ct=330000J/kg
E₁=m·c·Δt
E₁=0,1kg·2100J/kg·°C·10°C=2100J
E₂=m·ct
E₂=0,1kg·330000J/kg=33000J
E=33000J+2100J=35100J=35,1kJ
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m=100g=0,1kg
Δt=10°C
c=2100J/kg·°C
ct=330000J/kg
E₁=m·c·Δt
E₁=0,1kg·2100J/kg·°C·10°C=2100J
E₂=m·ct
E₂=0,1kg·330000J/kg=33000J
E=33000J+2100J=35100J=35,1kJ