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2 mole H₂ -- 2 mole wody
x -- 6 moli wody
x = 6 moli H₂
1 mol H₂ ---- 22,4 dm³
6 moli H₂ --- x
x = 134,4 dm³
Odp. Do otrzymania 6 moli potrzeba 134,4dm³ wodoru.
6 moli H₂ = x
x = 134,4 dm³