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masa propanu = 11g
szukane: V(O2)=?
C3H8+5O2=3CO2 + 4H2O
Obliczamy liczbe moli propanu
masa molowa = 44g/mol
n=m/M => 11/44 = o,25mola, to ilosc moli tlenu =5*0.25=1.25mola
to objetosc V=n*Vo
V=1.25*22,4 = 28dm3