ile dm^3 siarkowodoru otrzymamy ze 150 gram 5% roztworu siarczku sodu?
mNa2S=78u
Z def. stęż. procent.
5g Na2S------100g roztworu
xgNa2S-------150g roztworu
x = 7,5g Na2S
Na2S + H2SO4---->Na2SO4 + H2S
78g Na2S--------22,4dm3 H2S
7,5g Na2S---------xdm3 H2S
x = 2,15dm3 H2S (siarkowodoru)
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mNa2S=78u
Z def. stęż. procent.
5g Na2S------100g roztworu
xgNa2S-------150g roztworu
x = 7,5g Na2S
Na2S + H2SO4---->Na2SO4 + H2S
78g Na2S--------22,4dm3 H2S
7,5g Na2S---------xdm3 H2S
x = 2,15dm3 H2S (siarkowodoru)