Ile cm³ należy dodać do 0.5 kg 10% octu żeby otrzymać ocet stołowy 6%
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Cp1 - 10%
Cp2 - 6%
masa substancji = 10% x 500g = 50g
50g = 6% x masa roztworu 2
masa roztworu = 833,3g
833,3g - 500g = 333,3g
333,3g = 333,3 cm3