Ile chlorobutanu powstanie w reakcji 15g butanu z chlorem?
mC4H10=58u
mC4H9Cl=92,5u
C4H10 + Cl2 ---> C4H9Cl + HCl
58g butanu ----- 92,5g chlorobutanu
15g butanu ------ xg chlorobutanu
x = 23,9g chlorobutanu
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mC4H10=58u
mC4H9Cl=92,5u
C4H10 + Cl2 ---> C4H9Cl + HCl
58g butanu ----- 92,5g chlorobutanu
15g butanu ------ xg chlorobutanu
x = 23,9g chlorobutanu