If the sum of 5 different positive integers is 100, what is the greatest possible value for the median of the 5 integers? jawab pake cara yes thanks
acim
Let the numbers are a, b, c, d , and e with a < b < c < d < e obvious, c as the median. to get the greatest median, then the first of 2 numbers must be minimum ((a,b) = (1,2) , (1,3), ... etc)) and the 3 last numbers (c,d, and e) are consecutive positive integers.
just trials : if a = 1 and b = 2, then supposed c = x , d = x+1, and e = x + 2 give us : 1 + 2 + x + x + 1 + x + 2 = 100 3x + 6 = 100 3x = 94 x = 94/3 = 31.33 (it is not an integer) others : if a = 1 and b = 3, then let c = x, d = x+1, and e = x+2, give us : 1 + 3 + x + x + 1 + x + 2 = 100 3x + 7 = 100 3x = 100 - 7 3x = 93 x = 93/3 = 31 therefore, the greatest possible value as the median is 31
obvious, c as the median. to get the greatest median, then the first of 2 numbers must be minimum ((a,b) = (1,2) , (1,3), ... etc)) and the 3 last numbers (c,d, and e) are consecutive positive integers.
just trials :
if a = 1 and b = 2, then supposed c = x , d = x+1, and e = x + 2
give us :
1 + 2 + x + x + 1 + x + 2 = 100
3x + 6 = 100
3x = 94
x = 94/3 = 31.33 (it is not an integer)
others :
if a = 1 and b = 3, then let c = x, d = x+1, and e = x+2,
give us :
1 + 3 + x + x + 1 + x + 2 = 100
3x + 7 = 100
3x = 100 - 7
3x = 93
x = 93/3 = 31
therefore, the greatest possible value as the median is 31