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4x-3y=7 (2)
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6x-6y=9 ⇔ 2x-2y=3 ⇔ x-y=3/2 ⇔ x=3/2+y (3)
(3) kita substitusikan ke (1) diperoleh
2x+3y-6z=2 ⇔ 6z=2x+3y-2 ⇔ 6z=2(3/2+y)+3y-2 ⇔ 6z=3+2y+3y-2 ⇔ 6z=1+5y ⇔ z=1/6+5/6z
HP={(x.y,z)}={y|(3/2+y,y,1/6+5/6z), y∈bilangan real}
Semangat!