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=> log x^2 ≤ log (x + 3).4
=> x^2 ≤ 4x + 12
=> x^2 - 4x - 12 ≤ 0
=> (x - 6)(x + 2) ≤ 0
=> x = 6 atau x = -2
garis bilangan
+++ (-2) --- (6) +++ => krn ≤ maka daerah nya yg --- (negatif)
syarat
1) x > 0
2) x + 3 > 0 => x > -3
irisan dari garis bilangan
........ [-2] xxxxxxxxx [6] ...........
.......................(0) xxxxxxxxxxxx
..(-3)xxxxxxxxxxxxxxxxxxxxxxx
HP = {x | 0 < x ≤ 6, x € R}