Question

hola, tengo q resolver las divisiones de expresiones algebraicas paso a paso​

Answer 1

Verified answer

Explicación paso a paso:

1)

[tex](x {}^{3} - 6x {}^{2} - 5x + 2) \div (x - 1) \\ x - 1 = 0 \\ x = 1[/tex]

2)(

[tex](x {}^{5} - 4x {}^{3} + 1 + x {}^{2} - 1 \\ x {}^{5} - 4x {}^{3} + x {}^{2} [/tex]

3)

[tex](x {}^{6} - 1) + (x {}^{2} - 1) \\ x {}^{6} - 1 + x {}^{2} - 1 \\ x {}^{6} - 2 + x {}^{2} \\ x {}^{6} + x {}^{2} - 2[/tex]