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Así 7log(3x)=7log(3)+7log(x)
3log(5x)=3log(5)+3log(x) luego
7Log(3x)+3log(5x)=15
<=>
10log(x)=15-3log(5)-7log(3)
Log(x) =( 5-3log(5)-7log(3)) /10
X =exp[( 5-3log(5)-7log(3)) /10]
Saludos..