Question

hola como están me podrían ayudar porfas si no es mucha molestia​

Answer 1

Verified answer

Respuesta:

Explicación paso a paso:

6 )

[tex]Radio: R= 12m[/tex]

[tex]Angulo: \alpha =30[/tex]

[tex]\pi =3.14[/tex]

Area del sector circular: [tex]Asc = ?[/tex]

Fórmula:

[tex]Asc = \frac{\pi R^{2}\alpha }{360}[/tex]

[tex]Asc= \frac{\pi (12m)^{2}(30) }{360} =\frac{(3.14)(144m^{2} )(30)}{360} =\frac{13571.68m^{2} }{360 }[/tex]

[tex]Asc= 37.7m^{2}[/tex]

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9 )

[tex]Radio-mayor: R = 8cm[/tex]

[tex]Radio-menor: r = 6cm[/tex]

[tex]\pi =3.14[/tex]

Area de la corona circular: [tex]Ac = ?[/tex]

[tex]Formula:[/tex]

[tex]A = \pi (R^{2} -r^{2} )[/tex]

[tex]Ac = \pi ( 8^{2} -6^{2} ) = \pi ( 64-36) = \pi (28cm^{2} )[/tex]

[tex]Ac = 28\pi cm^{2}[/tex]

[tex]Ac = (3.14)(28cm^{2} )[/tex]

[tex]Ac = 87.92cm^{2}[/tex]

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10 )

[tex]Lado: a = 10m[/tex]

[tex]Lado: b = 8cm[/tex]

[tex]Lado: c = 6cm[/tex]

[tex]\pi =3.14[/tex]

[tex]Radio: R = ?[/tex]

Area sombreada: [tex]As = ?[/tex]

Fórmula:

[tex]R = \frac{b+c-a}{2} =\frac{8m+6m-10m}{2} = \frac{14m-10m}{2} =\frac{4m}{2}[/tex]

[tex]R = 2m[/tex]

[tex]As = \pi R^{2}[/tex]

[tex]As = \pi (2m)^{2} = \pi (4m^{2} )[/tex]

[tex]As = 4\pi m^{2}[/tex]

[tex]As = (4)(3.14) m^{2}[/tex]

[tex]As = 12.56m^{2}[/tex]