5) (i) 14x² - 23x + 8= 14x² - 16x - 7x + 8= 2x(7x - 8) - 1(7x - 8)= (7x - 8)(2x - 1)5) (ii) 12x² - x - 35= 12x² + 20x - 21x - 35= 4x(3x + 5) - 7(3x + 5)= (3x + 5)(4x - 7)6) (i) 6x² + 11x - 10= 6x² + 15x - 4x - 10= 3x(2x + 5) - 2(2x + 5)= (2x + 5)(3x - 2)6) (ii) 5 - 4x - 12x² = 5 + 6x - 10x - 12x² = 1(5 + 6x) - 2x(5 + 6x)= (5 + 6x)(1 - 2x)#backtoschoolcampaign==========================Untuk contoh soal lainnya, bisa dilihat di link berikut :brainly.co.id/tugas/15923874===========================Kelas : 8Mapel : MatematikaKategori : Operasi AljabarKata Kunci : PemfaktoranKode : 8.2.1 (Kelas 8 Matematika Bab 1 - Operasi Aljabar)
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Verified answer
5) (i) 14x² - 23x + 8
= 14x² - 16x - 7x + 8
= 2x(7x - 8) - 1(7x - 8)
= (7x - 8)(2x - 1)
5) (ii) 12x² - x - 35
= 12x² + 20x - 21x - 35
= 4x(3x + 5) - 7(3x + 5)
= (3x + 5)(4x - 7)
6) (i) 6x² + 11x - 10
= 6x² + 15x - 4x - 10
= 3x(2x + 5) - 2(2x + 5)
= (2x + 5)(3x - 2)
6) (ii) 5 - 4x - 12x²
= 5 + 6x - 10x - 12x²
= 1(5 + 6x) - 2x(5 + 6x)
= (5 + 6x)(1 - 2x)
#backtoschoolcampaign
==========================
Untuk contoh soal lainnya, bisa dilihat di link berikut :
brainly.co.id/tugas/15923874
===========================
Kelas : 8
Mapel : Matematika
Kategori : Operasi Aljabar
Kata Kunci : Pemfaktoran
Kode : 8.2.1 (Kelas 8 Matematika Bab 1 - Operasi Aljabar)