Jawaban:
a. 4,48 L
b. 4,8 L
c. 5,6 L
Penjelasan:
massa SO3 = 16 gr
a. (STP) Keadaan Standar (0°C)
V = n × 22,4
V = (massa SO3/Mr SO3) × 22,4
= (16/(1 × Ar S) + (3 × Ar O)) × 22,4
= (16/80) × 22,4
= 0,2 × 22,4
= 4,48 L
b. (RTP) Dalam Keadaan 25°C (P = 1 atm)
V = n × 24
V = 0,2 × 24
= 4,8 L
c. n SO3/V SO3 = n N2/V N2
0,2/ V SO3 = 0,25/7
0,25 V SO3 = 0,2 × 7
0,25 V SO3 = 1,4
V SO3 = 1,4/0,25
= 5,6 L
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Jawaban:
a. 4,48 L
b. 4,8 L
c. 5,6 L
Penjelasan:
massa SO3 = 16 gr
a. (STP) Keadaan Standar (0°C)
V = n × 22,4
V = (massa SO3/Mr SO3) × 22,4
= (16/(1 × Ar S) + (3 × Ar O)) × 22,4
= (16/80) × 22,4
= 0,2 × 22,4
= 4,48 L
b. (RTP) Dalam Keadaan 25°C (P = 1 atm)
V = n × 24
V = 0,2 × 24
= 4,8 L
c. n SO3/V SO3 = n N2/V N2
0,2/ V SO3 = 0,25/7
0,25 V SO3 = 0,2 × 7
0,25 V SO3 = 1,4
V SO3 = 1,4/0,25
= 5,6 L